People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.

There are four combinations of coins to pay ten credits:

ten 1-credit coins,

one 4-credit coin and six 1-credit coins,

two 4-credit coins and two 1-credit coins, and

one 9-credit coin and one 1-credit coin. 

Your mission is to count the number of ways to pay a given amount using coins of Silverland.

Input

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

Output

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.

 

Sample Input

2

10

30

0

Sample Output

1

4

27

 

时间复杂度：

题解：动态规划

代码：

#include 
     
      using namespace std;int coin[20] = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289};int a[333][333];int money;int main() {    while(~scanf("%d", &money)) {        memset(a, 0, sizeof(a));        if(money == 0)            break;        a[0][0] = 1;        for(int i = 0; i < 17; i ++) {            for(int j = coin[i]; j <= money; j ++) {                for(int k = 1; k < 300; k ++) {                    if(j >= coin[i])                        a[k][j] += a[k - 1][j - coin[i]];                }            }        }        int sum = 0;        for(int i = 0; i < 300; i ++)            sum += a[i][money];        printf("%d\n", sum);    }    return 0;}